Test Final #1

  False

  True

  an Israeli computer scientist called John Benjamin

  a Nigerian software engineer named Freddy Kalu

  a Dutch programmer named Guido Van Rossum

  an Australian woman by the name of Gelda Van Minch.

  All of these options are valid!

  Game design, web development and machine learning

  use in the backend systems of companies like Youtube, Facebook and Google

  the creation of desktop applications

Python, please print the words "hello world" to the screen. 

  True

  False

x=2
y=4
z=x+y
print(z)

  6

  x

  z

  0

  a varying piece of code that changes all the time e.g. print(x)

  a value box for storage e.g. 2 = x, where 2 is the variable

  a storage box for values e.g. x = 2, where x is the variable

  a number, or word that can change itself automatically

x=2
y=8
z=0
total=x+y+z
print(total)

  3 variables: x,y and z

  2 variables: x and y

  4 variables: x,y,z and total

  There are no variables in the code

2,7,5,88,9,73,23,90,18

  False

  True

9,	15,	13,	18,	11,	8, 7,

  start at the beginning and then continue to look through each element in turn

  start at 7 because the term 'linear' means 'last'

  start at the middle as that is where 18 is

  start at the second element

  it was first suggested by Napoleon who believed in the slogan: "Divide and Conquer"

  it conquers the problem much faster than any other searching algorithm

  it splits the list into two halves as part of the algorithm, and finds the mid point

  it is called 'Binary Search' and the word 'Binary' means divide

  False

  True

  Usually, a Binary search is more efficient on a sorted list, except in the case of a very short list

  A Binary search is more efficient because Binary means 'two' and 'two' is better than 'one'

  A Linear search is definitely quicker especially for lists that are longer than a million elements

  A Linear search is always much quicker, especially if the list is sorted and very long

[3, 5, 6, 8, 11, 12, 14, 15, 17, 18]

  First 18 (the last element) and then 3(the first element)

  First 12 (the midpoint) and then the midpoint of the first half of the list which is 6

  First 3 (the first element) and then the midpoint of the list which is 12

  You would find 8 immediately if you were using a Binary search algorithm

def main()
  print("This is the main subroutine"

def subroutine1():
print("This is subroutine1")
  

def subroutine2:
  print("This is subroutine2")
  
subroutine1()

  "This is the main subroutine"

  "print"

  "This is subroutine2"

  "This is subroutine1"

def facebook():
	print("Welcome to your facebook profile")

#what do you need to add here to make this program run?

  call facebook:

  print(facebook())

  def facebook

  facebook()

def main():
  #Set Seat to True if booked, False if available
  seat1booked=True
  seat2booked=False
  seat3booked=False
  seat4booked=True
  
  print("Seat 2 is booked?:",seat2booked)

main()

  Seat 2 is booked?: seat2booked

  print("Seat 2 is booked?:",seat2booked

  Seat 2 is booked?: True

  Seat 2 is booked?: False

def main():
  x=2
  y=3
  add(x,y)

def add(x,y):
  print(x+y)

main()

  False

  True

def main():
  x=2
  y=3
  add(x,y)

def add(x,y):
  print(x+y)

main()

  Parameter passing: the variables x and y are being passed to the function 'add'

  Joining: This line is simply joining together x and y using a comma

  Addition: This line is adding up the variables x ad y

  Bonding: Here the variables x and y are being encouraged to be close

def main():
  x=10
  y=20
  z=30
  avg=average(x,y,z)
  print(avg)
 
def average():
  return (x+y+z)/3

main()

  The parameter 'avg' is missing. It should be: def average(avg):

  The parameters x,y,z! It should be: def average(x,y,z):

  Nothing is missing!

  The variables a,b,c! It should be: def average(a,b,c):

def areaOfRectangle():
 width= int(input("Enter width:"))
 height=int(input("Enter height:"))
 area=width*height
 print(area)

areaOfRectangle()

  It will work perfectly and output the area of the piece of land

  Error! the 'int' on line 2 and 3 should be changed to 'float' which is an appropriate data type for this input

  Error! the 'int' on line 2 and 3 should be changed to 'str' (string)

  It will round off the answer to provide one whole number answer

celsius=int(input("Enter the temperature in celcius:"))
fahrenheit=(celsius*1.8)+32
print("Temperature in farenheit is:",f)

  Line 2: This line should be deleted

  Line 1: "celsius" should be in speech marks

  Line 2: "fahrenheit" should be "f" or Line 3, "f" should be "fahrenheit" so they match

  There are no errors - the code will work fine

def convert_to_dollars():
  pounds=input("Enter no. of pounds:")
  dollars=pounds*2
  print(dollars)

convert_to_dollars()

  Because 10*2 in python will always give 1010

  Because dollars are always provided in multiples of 10

  Because the user input on line 2 is string. It simply puts '10' together twice

  Because there is a mistake on Line 6

a="apple"
b="number"
c=1
d=5
e=True
f=False
g=202.27

  False

  True

  string

  integer

  boolean

  float

def find_average():
     test1=30
     test2=100
     test3=99
     #What needs to go here before calculating the average?
	 average=total/3     
     print("The average mark is:",average)
 
find_average()

  average=total

  total=test1+test2+test3

  You don't need to do anything on line 5. The code will work fine to calculate the average

  test1=test2+test3

  It is code that would ensure that only 'valid' input goes into the program

  It is code that looks, sounds and feels both elegant and valid

  A type of programmer that typically goes without valid conversation for months

  A type of computerised disease that causes great harm

  True

  False

  False

  True

try:
    value=int(input("Type a number:"))
except ValueError:
    print("This is not a whole number.")

  It will accept '3f' and say 'Thank you'

  It will print: "Type a number"

  It will print: "This is not a whole number"

  It will print: 0

def mainmenu():
  accepted_choices=["S"]
  choice=input("Press S to play:")
  if choice in accepted_choices:
    print("LET'S START")
  else: 
    print("Sorry, please make a valid choice")
   
mainmenu()

  Change line 2 to: accepted_choices=["S" or "s"]

  Delete line 2

  Change line 2 to: accepted_choices=["s"]

  Change line 3 to: choice=input("Press S and s to play:")

  will warn the user when the input is invalid and give them helpful suggestions

  will tell the user they are useless and refuse to let them input data again

  will invalidate the program by making it crash

  will scare the life out of the user by coding a hardware explosion.

  decision making, conditional logic and controlling the flow of a program

  creating a new function

  creating a loop

  ending a program without any fuss

num = 7
 
if num >= 0:
    print("Positive or Zero")
else:
    print("Negative number")  

  Else

  0

  Negative number

  Positive or Zero

def laptops():
    
     expensive_laptops=["HP Envy 100","Macbook Air","Microsoft Surface Pro"]
     cheap_laptops=["Asus primary 01","Toshiba X1","ChromeBook 12.2"]
 
     budget=int(input("How much can you spend on a laptop?"))
     if budget>=2000:
          print("Here are some laptops you could consider",expensive_laptops)
     else:
          print("You may want to check out these brands:",cheap_laptops)
     laptops()
 
laptops()

  The expensive_laptops list will be printed

  The cheap_laptops list will be printed

  4000 - 2000 = 2000. 2000 will be printed

  Both lists will be printed because 4000 is double 2000 which is the budget cut off

def email_check():
      
     email=input("We would like your email address. Please enter it:")
     if "@" in email:
     print("That is a valid email, Thank you")
     else:
     print("That doesn't appear to be a valid e-mail.")
 
email_check()

  Because emails do not have @

  Because there should be a bracket around the variable email

  Because line 5 and line 7 should be indented

  Because line 4 does not make sense

def main():
    x==0
    if x=0:
        print("x is greater than 2")
 
main()

  Line 2 is giving x a value of 0 so should be x=0, and line 3 should be: if x==0:

  The variable x can never ever be equal to zero

  There are no mistakes

  0 is not really a number so cannot be used in Python

def main():
print("This is the main function")
 
main()

  Line 3: blank space error

  Line 1: def main syntax error

  Line 4: blank brackets error

  Line 2: indentation error

def main():
  x=int(input("Enter a number:")
  print(x)
 
main()

  No, the error is that the line before is too long

  No, the error is that the line before is missing a colon from the end

  No, the error is on line 2 (missing bracket at the end)

  Yes, in this case the error is on line 3

score=20
if score>50
  print("You have passed!")
else:
  print("You have failed")

  Line 1 should be score==20 instead of score=20

  Line 2 is missing a colon at the end: e.g. if score > 50:

  Line 4 should be indented further along to the right

  Line 3 should not be indented

def instagram():
    print("Welcome Insta users")
     
     
     
    instagram()

  True

  False

age=30
if age>15:
  print("You are eligible for a bank account")
  else:
    print("Sorry, too young")

  if and else should be on the same level of indentation (else should be moved back)

  The problem is that the program discriminates against users that are over 15

  There is no problem. Indentation doesn't really matter in Python

  There should not be a colon after the if statement in line 2

x=2
y=6
z=x+y
q=x/y
r=x*y
print(r*3)

  x,y,z

  def, main, print

  +, - , /, *

  r,q

def main():
    score=1
    score=score+1 #this changes the value of score
    print(score)
 
main()

  1

  2

  0

  score

while True:
	print("Enter 'x' for exit.")
	rad = input("Enter radius of circle: ")
	if rad == 'x':
		break
	else:
		radius = float(rad)
		area = 3.14 * radius * radius
		print("Area of Circle",area)

  area = Ï€ x radius x 2

  area = 3.14 * rad * rad

  area = 3.14 * radius * radius

  area = 3.14 * rad(2)

while True:
	print("Enter 'x' for exit.")
	print("Enter two numbers: ")
	num1 = input()
	num2 = input()
	if num1 == 'x':
		break
	else:
		number1 = int(num1)
		number2 = int(num2)
		#What code do you need to write here?
			largest = number1
		else:
			largest = number2
		print("Largest of entered two numbers is", largest,"\n")

  if number2 > number1:

  if number1 < number 2:

  if number1 > number2:

  if number2 =< or => number1